3b^2+10=-51

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Solution for 3b^2+10=-51 equation: 



3b^2+10=-51

We move all terms to the left:

3b^2+10-(-51)=0

We add all the numbers together, and all the variables

3b^2+61=0

a = 3; b = 0; c = +61;
Δ = b2-4ac
Δ = 02-4·3·61
Δ = -732
Delta is less than zero, so there is no solution for the equation

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